What is the pressure at the base of a 60-foot-high cylinder if pressure increases by 0.434 PSIG per foot?

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Multiple Choice

What is the pressure at the base of a 60-foot-high cylinder if pressure increases by 0.434 PSIG per foot?

Explanation:
Hydrostatic pressure in a liquid column increases with depth at a constant rate. For water, that rate is about 0.433–0.434 psi per foot. If the top of the 60-foot-high cylinder is open to the atmosphere, the gauge pressure at the base equals the depth times that rate: 60 ft × 0.434 psi/ft ≈ 26.04 psi. So the base pressure is about 26 psi gauge. This matches the given data: a 60-foot height with a 0.434 psi/ft increase results in roughly 26 psi. The other options would require different heights (e.g., 60 psi would need ~138 ft; 32 psi ~74 ft; 12 psi ~28 ft), which don’t fit the 60-foot height.

Hydrostatic pressure in a liquid column increases with depth at a constant rate. For water, that rate is about 0.433–0.434 psi per foot. If the top of the 60-foot-high cylinder is open to the atmosphere, the gauge pressure at the base equals the depth times that rate: 60 ft × 0.434 psi/ft ≈ 26.04 psi. So the base pressure is about 26 psi gauge.

This matches the given data: a 60-foot height with a 0.434 psi/ft increase results in roughly 26 psi. The other options would require different heights (e.g., 60 psi would need ~138 ft; 32 psi ~74 ft; 12 psi ~28 ft), which don’t fit the 60-foot height.

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